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Mathematics 14 Online
OpenStudy (anonymous):

What are some examples on how to find the square root of a number.

OpenStudy (lgbasallote):

that depends...are you studying algebra or calculus? if you're in algebra the simplest way to find the square root of a number is factoring the radicand into perfect squares then taking those out of the radical in calculus you use linear approximation to get the value of square roots although there may be other ways of finding the square root of a number like using a calculator...or wolframalpha.com

OpenStudy (anonymous):

Im studying algebra.

OpenStudy (lgbasallote):

then follow the algebra portion of what i said

OpenStudy (anonymous):

square root of perfect square? or any number?

OpenStudy (anonymous):

x2 - 16 = 0 x2 = 16 \[\sqrt{x^{2}}\] = ±√16

OpenStudy (lgbasallote):

if you want to see an example of how the algebra thingy is done check this out http://openstudy.com/study#/updates/4fbae0ebe4b05565342fe421 maybe it can help you

OpenStudy (anonymous):

there is a very good article on wikipedia ... have you read it? http://en.wikipedia.org/wiki/Methods_of_computing_square_roots

OpenStudy (anonymous):

This is an example i was given but it makes no sence to me

OpenStudy (lgbasallote):

..oh that

OpenStudy (lgbasallote):

what part of that dont you get?

OpenStudy (anonymous):

\[ x^2 = 16 \\ x^2 = 4 \times 4 = -4 \times -4 = ( \pm 4)^2 \\ \text{so, }x = \pm 4\]

OpenStudy (anonymous):

What is ± mean?

OpenStudy (anonymous):

both plus also minus works ... see there ...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[ a^2 = b^2 \implies a = \pm b\]

OpenStudy (anonymous):

Can you give me another example of how to do this

OpenStudy (anonymous):

Solve for x: \[ x^2 - 25 = 0\]

OpenStudy (lgbasallote):

the square root of 16 is \(\pm 4\) because 4 x 4 is 16 and (-4) x (-4) is also 16 there fore both squares of 4 and -4 are 16..therefore \[\sqrt{16} \implies \pm 4\]

OpenStudy (anonymous):

ok so i know that the factors of 25 are 1 5 25

OpenStudy (anonymous):

so is the sqaure root 5

OpenStudy (anonymous):

\[ +5 \text{ and } -5 \]

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