HELP PLZZZ f(x) = 1/x determinate what is f(f(x)) and its domain
try this domain of f is the values of f(x) for which the fuction is defined. in this case. (3 - x) > = 0 ( square root has to be positive) so, 3 > =x so, x<=3. so, domain = ( - infinity, 3]
f(x)ception
f(f(x)) = f(1/x) = 1/(1/x) = x Domain = R
isn't the domain R except 0 ?
f(f(x)) = x What do you think?
welll, f(f(x)) = 1/(1/x). This is the original form, thus x can't be 0
yeah
1/(1/x) = x
x not equal 0
Domain = R-{0}
p/q q not equal 0 remember
lol can anyone confirm whatever 0 is included or excluded? :S its confusing
the limit as x -> 0 of f(f(x)) = 1 ;) but yes, as is, the domain is restricted by the parts that make it up, not by the algebra that defines an equivalent curve
so 0 is excluded??
see if this helps : domain of f(f(x)) = range of f(x) whats the range of f(x) ?
1/x excludes the zero
Well explained @ganeshie8.
OK
why did i type "1" ?? the limit as x -> 0 of f(f(x)) = 0
the domain is R
abay, no it isnt
ganesh, are you reading that as tho its an inverse? or am i misreading it?
i see it now ... whew!! thought i was going senile lol
thx guys!
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