Question

Simplify the expression.

Answer 1

\[\frac{(\csc y+\cot y)(\csc y -\cot y)}{\csc y}\]\[=\frac{\csc ^2y-\cot^2 y}{\csc y}\]\[=\frac{\csc ^2y}{\csc y}-\frac{\cot^2 y}{\csc y}\]\[=\]

Answer 2

sin y

Answer 3

wait - sin y

Answer 4

cot^x = cos^2 x/sin^2 x

Answer 5

what do i do next

Answer 6

work with sine and cosine to make life easier

Answer 7

i worked it out and -siny

Answer 8

nope it's sin y

Answer 9

\[=\frac{\csc ^2y}{\csc y}-\frac{\cot^2 y}{\csc y}\]\[={\csc y}-\frac{\cos^2 y/\sin^2y}{\csc y}\]\[=\frac{1}{\sin y}-\frac{\cos^2 y/\sin^2y}{1/\sin y}\]\[=\frac{1}{\sin y}-\frac{\cos^2 y}{\sin y}\]\[=\frac{1-\cos^2 y}{\sin y}\]\[=\]

Answer 10

\[=\frac{\sin^2 y}{\sin y}\]\[=\sin y\]