given f(x)= x2+3 and g(x)=x+5/x find (gof)(4)
(gof)(x)=g(f(x)). So instead of x's in g(x) you will have f(x). Can you continue from here?
@Traxter i still dont understand, can you work through it with me?
(gof)(x)=g(f(x))=g(x^2+3)=(x^2+3)+5/(x^2+3) When we evaluate at x=4, we get (gof)(4)=19+5/(19)
(Which simplifies to 366/19)
@Traxter so its like 19.3?
Yes, to one decimal place.
@Traxter it cant be, its either 14/19 or 24/19
When you wrote f(x)=x2+3, did you mean x squared by x2?
@Traxter Yes
@Traxter Sorry, my bad
given f(x)= x^2+3 and g(x)=(x+5)/x find (gof)(4)
Ok so we are taking g(x) composed with f(x) for x=4. So we will be taking g(f(4)). f(4)=4^2+3=16+3=19. Sub this into g(x). g(19)=(19+5)/19=24/19. It was the lack of brackets in g(x) that confused me. Note that x+5/x is not the same as (x+5)/x
\[ f(x)= x^2+3\] \[g(x)=\frac{x+5}{x}\] like that?
o then keep it x+5
i just wanted to not that x+5 is all over x
Then the last answer I gave is correct. Do you follow the working?
i'm so confused then because the answers dont match up. they have to be either 14/19 24/19 15 or -15
@Traxter
is \(g(x)=\frac{x+5}{x}\) right?
yes
Yes and I told you the answer is 24/19. Look through my solution: "Ok so we are taking g(x) composed with f(x) for x=4. So we will be taking g(f(4)). f(4)=4^2+3=16+3=19. Sub this into g(x). g(19)=(19+5)/19=24/19. It was the lack of brackets in g(x) that confused me. Note that x+5/x is not the same as (x+5)/x"
@Traxter ah i c
@Traxter has it for sure
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