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Mathematics 6 Online
OpenStudy (anonymous):

how do you find the limit of.......

OpenStudy (anonymous):

\[(\frac{ 1 }{ 2+x }-\frac{ 1 }{ 2 })/x\]

OpenStudy (anonymous):

as x goes to zero?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

do the algebra

OpenStudy (anonymous):

yes but 0 cannot be in the denominator

OpenStudy (anonymous):

\[\frac{1}{2+x}-\frac{1}{2}=\frac{2-(2+x)}{2(2+x)}=\frac{-x}{2(2+x)}\]

OpenStudy (anonymous):

do the algebra first, substitute last

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

now cancel the \(x\) top and bottom

OpenStudy (anonymous):

then you are left with 2x2=4 right?

OpenStudy (anonymous):

you see that \[\frac{\frac{1}{2+x}-\frac{1}{2}}{x}=\frac{-1}{2(2+x)}\]\]

OpenStudy (anonymous):

oh nevermind

OpenStudy (anonymous):

you are left with \(4\) in the denominator, yes, but you have a \(-1\) in the numerator

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

always works this way do the algebra first if you get a zero top and bottom, you will be able to factor and cancel then substitute

OpenStudy (anonymous):

alright thanks so much

OpenStudy (anonymous):

yw

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