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how do you find the limit of.......
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\[(\frac{ 1 }{ 2+x }-\frac{ 1 }{ 2 })/x\]
as x goes to zero?
yes
do the algebra
yes but 0 cannot be in the denominator
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\[\frac{1}{2+x}-\frac{1}{2}=\frac{2-(2+x)}{2(2+x)}=\frac{-x}{2(2+x)}\]
do the algebra first, substitute last
ok
now cancel the \(x\) top and bottom
then you are left with 2x2=4 right?
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you see that \[\frac{\frac{1}{2+x}-\frac{1}{2}}{x}=\frac{-1}{2(2+x)}\]\]
oh nevermind
you are left with \(4\) in the denominator, yes, but you have a \(-1\) in the numerator
ok
always works this way do the algebra first if you get a zero top and bottom, you will be able to factor and cancel then substitute
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alright thanks so much
yw
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