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OpenStudy (anonymous):
Write a linear factorization of the function.
f(x) = x4 + 16x2
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hartnn (hartnn):
write x^4 as x^2*x^2....then take out x^2 common...can u do this?
OpenStudy (anonymous):
take x2 common
OpenStudy (anonymous):
f(x) = x^2 (x^2 + 16)
OpenStudy (anonymous):
there you go! (:
OpenStudy (anonymous):
I got f(x) = x2 (4x + i)(4x - i)
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OpenStudy (anonymous):
hmm, I didn't know that you were asking to factor so far.
Are there answer choices?
hartnn (hartnn):
its should be f(x) = x2 (x + 4i)(x - 4i)
check again...
OpenStudy (anonymous):
How did you get (x + 4i)(x- 4i) ? @hartnn
hartnn (hartnn):
do u know what 'i' stands for??
OpenStudy (anonymous):
Imaginary number. A negative radical. i = -1
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hartnn (hartnn):
its an imaginary number,but its square root of -1
hartnn (hartnn):
\[\sqrt{-1}=i\]
OpenStudy (anonymous):
I know...
OpenStudy (anonymous):
So how did you find the sum of squared roots?
hartnn (hartnn):
ok,so \[\sqrt{a^2+b^2}=(a+i*b)(a-i*b)\]
i have used this...now it would be clear to u...
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OpenStudy (anonymous):
Thanks (: I gave you a medal! @hartnn
hartnn (hartnn):
@gps she asked whether its f(x) = x2 (4x + i)(4x - i) which means she knew it...
@Lol9999 thanks
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