Question

can someone solve this radical question?

Answer 1

\[\sqrt{5 - 2x} - \sqrt{2 - x} - \sqrt{3 - x} = 0\]

Answer 2

solve for x

Answer 3

first take one of the square root sign on other side and square it
then isolate the only square root sign on one side and square again.....

Answer 4

@Lol9999 please tell what you get after getting awesome guidance/instructions from @hartnn

Answer 5

Please do reply..

Answer 6

:P

Answer 7

... Lol, I'm a bit dazzled.

Answer 8

More concrete work please?

Answer 9

So do I just find the square root of both sides?

Answer 10

oh k ..
\[\large{\sqrt{5-2x}-\sqrt{2-x}-\sqrt{3-x}=0}\]
\[\large{\color{blue}{\sqrt{5-2x}-\sqrt{2-x}=\sqrt{3-x}}}\]

what i did was that just added \(\large{\sqrt{3-x}}\) both sides

Answer 11

now square both sides :
\[\large{\color{green}{(\sqrt{5-2x}-\sqrt{2-x})^2=(\sqrt{3-x})^2}}\]

Answer 12

Can you do it now @Lol9999 ?

Answer 13

lemme know what you get after what simplifying that

Answer 14

Thanks (:

Answer 15

no problem and also :
\[\huge{\color{blue}{\cal{Welcome}}\space \color{green}{\textbf{TO}}\space \color{red}{\mathbb{OpenStudy}}}\]