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Mathematics 21 Online
OpenStudy (jpsmarinho):

Is this correct? Trigonometric integral:

OpenStudy (jpsmarinho):

OpenStudy (anonymous):

second last step

hartnn (hartnn):

only in the last step \[u^{-1/2} = 1/(\sqrt{\sin a})\] and not only sin a in denominator.... rest is correct...

OpenStudy (anonymous):

integral of u^-1/2 gives u^+1/2

hartnn (hartnn):

and yes it should be u^(+1/2) as told by @telltoamit ...which will give u sqrt(sin a) in numerator

OpenStudy (jpsmarinho):

Thanks!!!

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