Question

solve for x

x\[x^2 + \sqrt(3x) +3=0\]

Answer 1

x\[x^2 + \sqrt(3x) +3=0\]

Answer 2

help please???

Answer 3

try raising everything to ^2 at first

Answer 4

right then i get x^4 +3x+9=0

Answer 5

this is where im stuck

Answer 6

assume x2=y

Answer 7

and replace

Answer 8

y^2+3x+9=0

Answer 9

actually do you know complex numbers?

Answer 10

yes

Answer 11

cause this is only complex. ok. from the beginning then.
rewrite sqrt3x somehow else

Answer 12

3x^.5

Answer 13

nah. I guess sqrt3*sqrtx
is comfier

Answer 14

then, u get x^2+sqrt3*sqrtx=-3 which gives you 2 complex roots, cause a ^2 can't be negative in R