Can someone please explain how to solve this problem? I don't remember planes... In the xy-plane, what is the slope of the line whose equation is 3x-2y=8?
First solve for y. Do you know how to do this?
I think so, like this?: subtract 3x from each side: -2y=8-3x divide each side by -2 y=8-3x |dw:1345662293560:dw| -2
um, that didn't come out right. I was trying to show that 8-3x is over -2
like this \[\Large 3x-2y=8\] \[\Large -2y=8-3x\] \[\Large y=\frac{8-3x}{-2}\] ??
precisely
Keep going and simplify it into y = mx+b form
THAT I don't know
\[\Large 3x-2y=8\] \[\Large -2y=8-3x\] \[\Large y=\frac{8-3x}{-2}\] \[\Large y=\frac{-3x+8}{-2}\] \[\Large y=\frac{-3x}{-2}+\frac{8}{-2}\] \[\Large y=\frac{3}{2}x-4\] Notice how the last equation is in y = mx+b form where m = 3/2 and b = -4
Ok, I guess that could make sense. But then what does that mean? I still don't understand where y is if I were to chart it on the graph
and what does "slope of the line" mean?
y = mx+b is the general equation of any line
The value of m is the slope
The point (0,b) is the y-intercept
Ok, so 3/2 is the slope then?
yes, this represents how "steep" or "shallow" the line is
it also represents if the line goes up or down (as you read it from left to right)
ok, so if I were to graph this, what would it look like?
You would plot a point at (0,-4), which is the y-intercept
Here is a video, on graphing http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/v/graphs-using-slope-intercept-form he also has other videos about lines that might be helpful
Then you would go up 3 units, then to the right 2 units to get to the next point (2, -1)
You now have two points. Draw a straight line through them to graph the line.
Cool, thank you for all your help, jim! Also, thank you, phi for the vid link, I'll check it out :)
you're welcome
This one looks more appropriate for how to graph the line http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/v/algebra--graphing-lines-1
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