Find the perimeter of a square having two consecutive vertices at (7, 2) and (-3, 3). A.4sqrt17 B.4sqrt101 C.20sqrt3 D.4sqrt3
Find the distance from (7, 2) to (-3, 3)
Then multiply that distance by 4 to find the perimeter
i got 1/-10 for distance
is that right?
no, it cfant be right...
no, the distance has to have a square root in it
well, how do i find that? i'm sorry if i seem a little slow, but i failed a class last year, and now i have to do it over the computer, so i've been through a whole year in about a week
but luckily, im already at 90%(: thats why i ask so many questions, this last workseet has 80 problems on it
I'll show you how to find the distance between these two points and hopefully it will be useful for finding the distance between any two points (so I recommend copying this into your notes) d = sqrt((x2-x1)^2+(y2-y1)^2) d = sqrt((-3-7)^2+( 3- 2)^2) d = sqrt((-10)^2+(1)^2) d = sqrt(100+1) d = sqrt(101) So exact distance between the two points is sqrt(101) units.
and i dont wanna rush, but i only have half an hour left, and bout 50 questions, so asap please & yeah i've been taking lots of notes..
so if the distance is sqrt(101), what's the perimeter?
4sqrt101?
you got it
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