Find the angle that is supplementary to θ. (a) θ = 46°51'31''
Oh yes Trig got to love it!!
lol rite !! i need help
is A the problem or an answer choice? Just asking..
problem
okay
I am still here I am just making sure I tell you the right way to do this problem.
ok thnx
okay look at this website http://math.berkeley.edu/~mcivor/math53su11/solutions/hw1solution.pdf
I will read it as well
Its pretty easy to do.
its 133-8-29 i figured it out
I know it is easy i have not done this problem for a while Hero please help
boopie good job
Minutes and degrees have to add to 60. That's all you needed to know @godorovg
duh thanks
hero i have a new question !!!!
Just a second ago you were saying "Hero please help".
yes I had forgot that min, seconds and the other stuff just posted. And me saying duh thanks it jingled my mind again I am rusty on some of this stuff I just sometimes need someone to say hey it's this.
hero I will go and let you handle this one.
Express the angle as a decimal, to the nearest ten - thousandth of a degree. 256° 17' 44''
I don't really know the answer to that offhand. Post it as a new question.
i did
No, I mean for you to close this current post. Then post a new post with your new question in it.
i did this been closed once i figured the answer
So post a NEW post with your new question.
i did 11 minutes ago
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