Use the image shown below to answer the question that follows.
The two-column proof below proves the following theorem: The three medians of a triangle all intersect in one point.
Which reason is missing from the proof?
Properties of a Parallelogram
By Construction
Midsegment Theorem
Intersecting Lines Postulate
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
can you help me????
OpenStudy (anonymous):
@UnkleRhaukus
OpenStudy (anonymous):
Got it?
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OpenStudy (anonymous):
this my last question but I REALLY do not understand it
OpenStudy (anonymous):
no
jimthompson5910 (jim_thompson5910):
notice we have triangles ABH and ACH
jimthompson5910 (jim_thompson5910):
what kind of segment is FG to ABH?
OpenStudy (anonymous):
I am not sure
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jimthompson5910 (jim_thompson5910):
F is the midpoint of AB
jimthompson5910 (jim_thompson5910):
G is the midpoint of AH
OpenStudy (anonymous):
alright
jimthompson5910 (jim_thompson5910):
so FG is the _____ of triangle ABH
what goes in the blank?
OpenStudy (anonymous):
the perpendicular bisector?
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jimthompson5910 (jim_thompson5910):
not quite
jimthompson5910 (jim_thompson5910):
The points are midpoints and they form a segment
jimthompson5910 (jim_thompson5910):
midpoints...segment....
jimthompson5910 (jim_thompson5910):
keywords that form the name
OpenStudy (anonymous):
oh ok
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