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Mathematics
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OpenStudy (anonymous):
questions 1 and 2
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OpenStudy (australopithecus):
nice file directory
OpenStudy (anonymous):
i tried to screenie the question to show u guys idk how to do it properly..
OpenStudy (australopithecus):
hit attach file and upload the file
OpenStudy (anonymous):
ok i think i got it
OpenStudy (australopithecus):
|dw:1345672998315:dw|
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OpenStudy (anonymous):
:o?
OpenStudy (anonymous):
its already simplified right
OpenStudy (australopithecus):
I'm saying
\[x^{-1} = \frac{1}{x^1} = \frac{1}{x}\]
OpenStudy (australopithecus):
x^-1 is the same as 1/x
OpenStudy (anonymous):
ye and the second?
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OpenStudy (australopithecus):
you can express anything to the power of 1 so we just dont write the 1 as an exponent
OpenStudy (anonymous):
u dont mind if u stay with me till i finish and bare with me while i upload screenies
OpenStudy (australopithecus):
since you know the rule can you express the equation not as a fraction
OpenStudy (australopithecus):
For example x/y = x(y^(-1))
OpenStudy (anonymous):
what was number 2?
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OpenStudy (australopithecus):
and when you multiply numbers with exponents you just add them
so
x^2(x^3) = x^(2+3) = x^5
OpenStudy (australopithecus):
I'm going over number 2
OpenStudy (australopithecus):
you simply use the rule you applied in the first question, then you add exponents on similar variables
OpenStudy (anonymous):
basically x2+ x3= x5?
OpenStudy (australopithecus):
no you dont add exponents when adding only when multiplying
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OpenStudy (anonymous):
oh
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