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Physics 11 Online
OpenStudy (anonymous):

1. The problem statement, all variables and given/known data A first stone is dropped from the roof of a building. 2.40 s after that, a second stone is thrown straight down with an initial speed of 33.0 m/s, and it is observed that the two stones land at the same time. (a) How long did it take the first stone to reach the ground? _____________ s (b) How high is the building? _____________ m (c) What are the speeds of the two stones just before they hit the ground? _____________ m/s (first stone) _____________ m/s (second stone)

OpenStudy (noelgreco):

Using \[s = \frac{ 1 }{ 2 } a t ^{2} + v _{o}t + h _{o}\] for each stone, the s terms will be equal to 0 when the stones hit the ground, thus the right sides may be equated. The h terms cancel, and you get a quadratic in t which can then be solved. Remember, the dropped stone's t is 2.40 s longer than the thrown stone - don't use two variables for the times.

OpenStudy (anonymous):

do you need only the final answer or what?

OpenStudy (anonymous):

the final answer....:)

OpenStudy (anonymous):

why do you smile :(

OpenStudy (anonymous):

cause i'm hoping that you'll give the answer? is that possible?

OpenStudy (anonymous):

sure just order me :)

OpenStudy (anonymous):

@K0GA wat do u mean? anyways i really have to verify.....

OpenStudy (anonymous):

i cannt understand what you mean

OpenStudy (anonymous):

@K0GA type your answer here

OpenStudy (anonymous):

iam sorry but its hard to open this site on my lab

OpenStudy (anonymous):

lets imagine that iam on the top of hospital and i dropped first stone from my hand from rest , then after 2.4 sec i throw second stone with intial speed 33 m\s

OpenStudy (anonymous):

(a) 5.3 sec

OpenStudy (anonymous):

(b) 137.6 m

OpenStudy (anonymous):

(c) 51.9 m\s ,,, 61.4 m\s

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