Question

Help I need to solve for A

0=a+b+4

1= a((1+sqrt5)/2) + b((1-sqrt5)/2) + 8

Answer 1

convert the first equation to be in terms of a or b

Answer 2

oh okay
thank you

Answer 3

come back and post your answer so we can see if its right

Answer 4

i end up with 1=a((1+sqrt5)/2)+(-a-4)((1-sqrt5)/2)+8
a comes out to be -5-2sqrt5
so b must be 9+2sqrt5

Answer 5

i have it diferently i get \[\frac{ -10+3\sqrt{5} }{ 5 }\]

Answer 6

as a and i get \[\frac{ -30+3\sqrt{5} }{ 5 }\] as b

Answer 7

wait n sec let me start again i did that horribly wrong

Answer 8

\[ 1=a(1+\frac{\sqrt5}{ 2 })+(-a-4)(1-\frac{\sqrt5}{ 2 })+8\]
to
\[1=a+\frac{ \sqrt{5} }{ 2 }a-a+\frac{ \sqrt{5} }{ 2 }a-4+2\sqrt{5}+8\]

Answer 9

is that right?

Answer 10

so the answer should be -2-sqrt5
i think i just simplified wrong the first
time

Answer 11

\[1=\sqrt{5} a+4+2\sqrt{5}\]

Answer 12

\[1-(4+2\sqrt{5})=\sqrt{5}a\]

Answer 13

\[-3-2\sqrt{5}=\sqrt{5}a\]

Answer 14

\[\frac{ -3-2\sqrt{5}}{ \sqrt{5} }=a\]

Answer 15

we both seem to be wrong on this one

Answer 16

what if if we do it as simultanoeus equations.....AO= a+b+41....(1) and AO=a(1+sqrt5)/2) +b(1-sqrt5)/2) +8....(2)