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Find the domain, range, x and y intercepts, and horizontal and vertical asymptotes of f(x) = 2/x^2-2x-3
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\[f(x)=\frac{2}{x^2-2x-3}\]The restrictions on the domain will be any values of x where the denominator is zero. In other words, you have to solve:\[x^2-2x-3=0\]Can you do this?
Yes, the answer would be x=3 or x=1
close. x=3 or x=-1
so when x is 3 or -1, the denominator is zero. We cannot divide by zero, so these values of x are not allowed. x can be any other real number other than these two. We write:\[D={x: x \in \mathbb{R}, x \neq3,x \neq -1}\]
Do you know any calculus?
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Ok, a vertical asymptote looks like this:|dw:1345683167924:dw|
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