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How do you simplify this rational expression?:
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\[\frac{ 3x+2 }{ 15x ^{2}+16x+27 }\]
you don't?
It says you can?
3x + 2 is not a factor of 15x^2 + 16x + 27
What about \[\frac{ x ^{2}+6x+9 }{ x ^{2}+12x+27 }\]
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I typed it wrong(sorry)
\[\frac{x^2 + 6x + 9}{x^2 + 12x + 27} = \frac{(x + 3)(x + 3)}{(x + 3)(x + 9)}\]
you can factor out the (x + 3)s
and say that it is (x+3)/(x+9)
I guess not so much factor out as really just cancel
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and I was talking about one (x+3) on the top and one (x+3) on the bottom
So the expression would be: \[\frac{ (x+3) }{ (x+9) }\]
yes
Thank you so much!
you are welcome
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