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OpenStudy (rainbow_dash):
\[2/x^2y - x/y\]
OpenStudy (alexwee123):
@Rainbow_Dash what do you think the first step should be?
OpenStudy (rainbow_dash):
uhh, cancel out like terms?
OpenStudy (alexwee123):
no that might come next after you add the fractions
OpenStudy (alexwee123):
so can you add the fractions for me?
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OpenStudy (alexwee123):
@Rainbow_Dash you there?
OpenStudy (rainbow_dash):
sorry was gone. okay so add the fractions
OpenStudy (rainbow_dash):
you got 2-x/x^2 * 2y?
OpenStudy (anonymous):
\[\frac{ 2-x^3 }{ x^2y } \]
OpenStudy (rainbow_dash):
how did you get that?
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OpenStudy (anonymous):
I don't know... I copied it from wolfram alpha
OpenStudy (anonymous):
:)
OpenStudy (rainbow_dash):
Ahaha.
OpenStudy (anonymous):
Lol JK I'll really show you how to do it. So, when you add fractions you know you have to find a common denominator, right? Well, to make y the same as x^2y, you have to multiply y by x^2.
OpenStudy (anonymous):
But what you do to the demoninator, you do to the numerator, so you'll get x*x^2, which is x^3. Now that both of the denominators are alike, you can subtract.
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