Use properties of limits to find the indicated limit. It may be necessary to rewrite an expression before limit properties can be applied. will post pic
this is limit
not sure how to factor out numerator
x approaches 1
yes that is the limit but if you use that the denominator becomes 0, undefined so i have to factor out numerator. how do i do that?
if i get the proper answer ill show hold up lol
u tried synthetic division
Yes, synthetic division will factor it nicely.
or just divide
use synthetic division with 1 x=1 will come out as factor you will be left with quadratic polynomial (x^2+6x+9) so x^3+5x^2+3x-9=(x-1)(x+3)^2
When you do the synthetic division, the x-1 terms will cancel out so you get a simple limit of a quadratic equation.
you know it is \(x^3+5x^2+3x-9)=(x-1)(ax^2+bx+c)\) so it does not take a lot of imagination to find \(a=1,c=9\) all you need really is \(b\)
so the answer is A? 16? since|dw:1345693944162:dw|
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