how to eliminate the arbitrary constant x^3 - 3x^2y = c?

Question

anonymous · Answer

just derivate once...

anonymous · Answer

with respect to $x$

anonymous · Answer

sir is this right? 3x^2 dx - 6x dx dy = 0?

anonymous · Answer

u must use product rule for derivating 3x^2y

anonymous · Answer

When you derive the x^3 it would be 3x^2 but when you derive the second term you have to use the product rule which is (the first term times the derivative of the second + the second term times the derivative of the first........fg=fg'+gf') So if you derive your problem it would end up being 3x^2-(3x^2+y6x)=0 I'm sure you can do the rest :) hope that helps

anonymous · Answer

sir what is the derivative of y with respect to x?

anonymous · Answer

dy/dx basically you are deriving y, it is dependent on x and x is your independent variable

anonymous · Answer

sir the final answer in the book is (x-2y) dx - x dy..where will dx and dy come from? sorry if this is a stupid question.. just bear with me, thanks