Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

What is the maximun of f(x)=3cosx+2sinx ? Whithout using derivatives

OpenStudy (lgbasallote):

how about limits? lol

OpenStudy (anonymous):

@seidi.yamauti are you aware of what the graphs of cosx and sinx look like?

OpenStudy (anonymous):

@abayomi12 he said without using derivatives.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I'd simplify this first: f(x) = 2 * sin(x) * cos(x) f(x) = sin(2x)

OpenStudy (anonymous):

max value of acosx+bsinx is sqrt(a^2+b^2) and min is -sqrt(a^2+b^2) thus here max value is sqrt(3^2+2^2)

OpenStudy (anonymous):

\[a\cos x+b\sin x=\sqrt{a^2+b^2} (\frac{a}{\sqrt{a^2+b^2}}\cos x+\frac{b}{\sqrt{a^2+b^2}}\sin x)\] using the fact that\[(\frac{a}{\sqrt{a^2+b^2}})^2+(\frac{b}{\sqrt{a^2+b^2}})^2=1\] u can prove\[\sqrt{a^2+b^2} (\frac{a}{\sqrt{a^2+b^2}}\cos x+\frac{b}{\sqrt{a^2+b^2}}\sin x)=\sqrt{a^2+b^2} \sin(x+\alpha)\]or\[\sqrt{a^2+b^2} (\frac{a}{\sqrt{a^2+b^2}}\cos x+\frac{b}{\sqrt{a^2+b^2}}\sin x)=\sqrt{a^2+b^2} \cos(x+\beta)\]

OpenStudy (shubhamsrg):

cool.. B|

OpenStudy (phi):

in other words, use the identity sin(x+y) = sin(x)cos(y)+cos(x)sin(y)

OpenStudy (anonymous):

maximum = sqrt(3^2 + 2^2) = sqrt(13)

OpenStudy (anonymous):

अगर आप चाहें तो वोल्फ्रम का उपयोग कर सकते हैं.

OpenStudy (anonymous):

बात समझ आई?

OpenStudy (anonymous):

@mukushla आप तो मास्टर हो, मास्टर!

OpenStudy (anonymous):

man this is hindi !

OpenStudy (anonymous):

ye cid walay yahan kya kar rahay hain :P

OpenStudy (anonymous):

@sami-21 Kya chal raha hai?

OpenStudy (anonymous):

@sami-21 chutti pe hain hum sab

OpenStudy (anonymous):

humari police

OpenStudy (anonymous):

btw just to let you know guys irreverent answers are considered as SPAM .

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

You can use a special trig identity: Acos(x) + Bsin(x) = Ccos(x-y), where C=\sqrt{A^2=B^2) and y = arctan(B/A). Hence \[f(x)=3\cos x + 2\sin x = \sqrt{13}\cos\left(x-arctan\tfrac{2}{3}\right)\approx\sqrt{13}\cos\left(x-.588\right)\] But in any case, the maximum for cos is 1, so the maximum for f(x) is the square root of 13.

OpenStudy (anonymous):

also \(a\sin(x)+b\cos(x)=\sqrt{a^2+b^2}\sin(x+\theta)\) for suitable \(\theta\) as i recall you can get this from "addition angle" formula

OpenStudy (anonymous):

@satellite73, how are you inserting equations without linebreaks? $ signs don't seems to work here (as they would in LaTeX).

OpenStudy (anonymous):

use \( instead of \[

OpenStudy (anonymous):

Thank you.

OpenStudy (anonymous):

you are right, $ does not work here turns out \( is an alternative in latex if you need to see any code, right click and you can see it. it is good method for copying and pasting as well, so you don't have to rewrite the latex every time

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!