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Mathematics 15 Online
OpenStudy (anonymous):

Investigate whether the following limits exist. For those that do exist, state the limit.

OpenStudy (anonymous):

OpenStudy (amistre64):

what does each piece equal to when x=1 ?

OpenStudy (anonymous):

Actually, I know where the limits exist or not now but I do not know how to find at which value it exists at.

OpenStudy (anonymous):

Can you help me out with these example? I know it has a limit but I do not know how to find it...

OpenStudy (amistre64):

a simple means is to draw the lines ona graph; and find where x=2 is at.

OpenStudy (amistre64):

x-4,x thats odd

OpenStudy (amistre64):

oh, x-4 , given that x is in the interval

OpenStudy (amistre64):

you do realize that x-4 is the same as x-4 ??

OpenStudy (anonymous):

yes I do, but the answers says that there is a limit.

OpenStudy (anonymous):

and so there isn't other way of determining the limit for these hybrid functions besides graphing it?

OpenStudy (amistre64):

this isnt a hybrid function :/

OpenStudy (amistre64):

from 0 to inf it is x-4 and everywhere else it is, x-4

OpenStudy (anonymous):

oh k, my bad. so it has to have a quadratic and linear or ....?

OpenStudy (amistre64):

a limit is defined when it approaches the same value from the left or the right (and in higher dimensions youll have to check all directions)

OpenStudy (amistre64):

in this case x=2 falls clearly within the top function (regardless of what the bottom function would be).

OpenStudy (amistre64):

since x-4 has no domain issues at x=2, the limit would be the value at x=2

OpenStudy (anonymous):

answer says -2

OpenStudy (amistre64):

2-4 = -2 ues

OpenStudy (anonymous):

ok, so it is basically substituting the value of x is approaching into the equation?

OpenStudy (amistre64):

yes

OpenStudy (anonymous):

so will it work for this?

OpenStudy (phi):

This video might help http://www.khanacademy.org/math/precalculus/v/introduction-to-limits

OpenStudy (amistre64):

notice that -2 is an issue within both intervals, top and bottom

OpenStudy (amistre64):

the only way a limit exists is if it approaches the same value from the left and the right plug in x=-2 into top and bottom and see if they produce the same value in this case

OpenStudy (anonymous):

yes, 0.

OpenStudy (amistre64):

then the limit exists, and is 0

OpenStudy (anonymous):

ok, I think I get it now, thanks.

OpenStudy (anonymous):

sorry @phi, I tend to stay away from KhanAcademy videos because they are quite messy, confusing and long.

OpenStudy (anonymous):

but thanks.

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