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calculate the following limits and represents the result you get (represents the asymptotes and associated curves in appropriate cases). \[\lim_{x \rightarrow + \infty} \left( x^{2}/3 - 2x \right)\]
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is this \[\frac{x^2}{3-2x}\]?
no
oh
\[\frac{x^2}{3}-2x\]?
\[\frac{ x2 }{ 3 } - 2x\]
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yes
@satellite73
this is a quadratic polynomial, therefore the graph is a parabola that opens up (because the leading coefficient is positive) therefore as \(x\) gets larger, it goes to infinity as well
i dont understand..
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as \(x\) gets larger, so does \(\frac{x^2}{3}-2x\) try it with \(x=10,000\) and see what you get
i got -33326
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