Question

intermolecular forces that are present in Argon

Answer 1

They are moslty vanderwaal forces since noble gases have completely filled orbitals

Answer 2

so it is a dispersion force only ?

Answer 3

Argon => non-polar => LDF

Answer 4

^good way to remember it

Answer 5

okay thank you so much ! but if u don't mind . I didn't understand that much about LDF

Answer 6

LDF is the intermolecular force present in both polar and nonpolar compounds

Answer 7

dispersion forces usually occur (if im not mistaken) as temporary dipoles. There is an instant wherein two atoms will have an orientation that is the same as the dipole-dipole.

Answer 8

oo okay . I got it . thanks again . but how about for NF3 and CH3OH , are these compounds LDF too ? or they are dipole-dipole or hydrogen bonds ?

Answer 9

they have LDF because like i said everything has LDF

they also have dipole-dipole because they are polar molecules

and they form hydrogen bonds... (not sure about NF3 though)

Answer 10

NF3 doesnt have h-bonding

Answer 11

NF3 just has LDF and dipole-dipole

Answer 12

that mean CH3OH is LDF . okay . but from what I understands . the dipole2 thinggy is just like double bonds right ?

Answer 13

dipole2 happens in polar molecules

Answer 14

what do you mean double bonds?

Answer 15

i'm a bit confuse with the bondings and the intermolecular forces . can you explain about it ?

Answer 16

okay...

POLAR MOLECULES => LDF + dipole2

IF the molecule has N-H, O-H or F-H then it also has H-bonding

NONPOLAR MOLECULES => LDF

nothing more; nothing less

Answer 17

okay . very clear explanation to me . thank you very very much for your respond :)

Answer 18

welcome ^_^

Answer 19

May I ask you more ?
I'm actually revising for my test .

Answer 20

sure..though i have to get to bed soon...

Answer 21

can you tell me why Na is written as [Ne]3s1 to show the short electron config ?

Answer 22

we're talking about electron config right?

Answer 23

that's an interesting question

Answer 24

yup :D

Answer 25

if you look at the periodic table, the noble gas BEFORE Na is Ne...that's why it has Ne at the start

then Na is at the first group and the third period...that's why 3s1...so that's why you have [Ne] 3s1

the full electron config of Na if im not mistaken is

1s2 2s2 2p6 3s1

then the electron configuration of Ne is 1s2 2s2 2p6

so you can just substitute Ne for 1s2 2s2 2p6 part of Na

does that help?

Answer 26

okay i need to sleep now so i hope that helped

Answer 27

okay tq so much . it helped me a lot . :)

Answer 28

welcome again