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Factor the following trinomial. w^18-9w^9y^5+14y^10
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w^18-9w^9y^5+14y^10 (w^9)^2 - 2* w^9* (9/2)y^5 +{(9/2)y^5}^2 - {(9/2)y^5}^2 + 14y^10
Does that help?
what you didnt post nothing
nvm i had to refresh the page
do yu know what i should write for my answer
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w^18 - 9w^9y^5 + 14y^10 The w^9 component of the middle term shows that the factors must contain w^9. The y^5 component, along with the y^10 product, shows that y^5 must be present too (along with coefficients that multiply to 14 and add to 9, such as 2 and 7). Experimenting with these conditions gives a factorization of (w^9 - 2y^5)(w^9 - 7y^5).
so should i just write the last part you gave me
yeah
ok Thanks
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