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Mathematics 6 Online
OpenStudy (anonymous):

Factor the following trinomial. w^18-9w^9y^5+14y^10

OpenStudy (anonymous):

w^18-9w^9y^5+14y^10 (w^9)^2 - 2* w^9* (9/2)y^5 +{(9/2)y^5}^2 - {(9/2)y^5}^2 + 14y^10

OpenStudy (anonymous):

Does that help?

OpenStudy (anonymous):

what you didnt post nothing

OpenStudy (anonymous):

nvm i had to refresh the page

OpenStudy (anonymous):

do yu know what i should write for my answer

OpenStudy (anonymous):

w^18 - 9w^9y^5 + 14y^10 The w^9 component of the middle term shows that the factors must contain w^9. The y^5 component, along with the y^10 product, shows that y^5 must be present too (along with coefficients that multiply to 14 and add to 9, such as 2 and 7). Experimenting with these conditions gives a factorization of (w^9 - 2y^5)(w^9 - 7y^5).

OpenStudy (anonymous):

so should i just write the last part you gave me

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

ok Thanks

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