Question

how much heat is released when 0.5kg of steam at 100◦C turns to order at a temperature at 20◦C ?

Answer 1

Q=m*c*(T2-T1) use c= specific heat capacity of water= 4.18, m= 0.5kg and T2-T1=80

Answer 2

m = m c t
m= 0.5 kg
c= 4200 j/kg/k
t= 80
put values get answer