Question

how do i find sin^-1(cos(pi)) and answer in radians in terms of pi

Answer 1

cos pi= -1 and sin^-1(-1)= ??

Answer 2

2n *pi+pi/2

Answer 3

how did you get that?

Answer 4

general solution of \[\sin^{-1}(-1)\] that means points at which sin is -1

Answer 5

okay that makes sense but i think i might have written the problem wrong. its: sin^-1(cospi). then it ask you to write your answer in radians in terms of pi

Answer 6

pi itself is in radian..and general solution is in radian too

Answer 7

okay so the answer i got is 2n multiplied by pi+pi/2

Answer 8

is that correct?

Answer 9

actually 2 multiplied by (pi+pi)/2

Answer 10

i think it must be (2k+1)pi + pi/2

Answer 11

well just use n= any integer....

Answer 12

does sin-1 =2pi