Question

Calculate an integral

Answer 1

Have you tried u-sub?

Answer 2

try u = 9-x^2

Answer 3

No, sub u=x^2

Answer 4

I'm pretty sure mine still works... Both are fine...

Answer 5

my substitution become like this...

Answer 6

Well you can trig sub if you want but that makes it needlessly complicated IMO.

Answer 7

emm what u suggest ?

Answer 8

I told u. u = 9-x^2.

Answer 9

Do you know how to u-sub?

Answer 10

\[u=x^2; \frac{ 1 }{ 2 }du = xdx\]

Answer 11

Again, either mine or james' work, since he keeps insisting....

Answer 12

you will get: \[\frac{ 1 }{ 2 }\int\limits_{0}^{1.6}(9-u)^{3/2}u du\]

Answer 13

for the integrand \[(9-u)^{3/2}u\] sub s=9-u and ds=-du

Answer 14

at this point you can expand the integrand and solve.

Answer 15

@jamesHayek I msged you but I'll tell you again: We don't want to give them most of the problem.

Answer 16

vf321, this is a site to help. Not bicker. Show your work to help her.

Answer 17

@jamesHayek help, not do homework for. But fine, this is not getting us anywhere. Let's stop arguing.

Answer 18

i am following ur step now. thx. trying to get the right answer

Answer 19

i will try both method