A diver jumps off of the high dive platform, which is 32.81 feet in the air. The diver's height (h) with respect to time(t) is noted by h(t)=-16t^2+18t+32.81.

a) Find the diver's height 1.5 seconds after they start their dive.
b) When is the diver at their maximum height?
c) What is the diver's maximum height?

Question

A diver jumps off of the high dive platform, which is 32.81 feet in the air. The diver's height (h) with respect to time(t) is noted by h(t)=-16t^2+18t+32.81.

a) Find the diver's height 1.5 seconds after they start their dive.
b) When is the diver at their maximum height?
c) What is the diver's maximum height?

anonymous · Answer

Please check my answers:
a) 23.81
b) 0.56 seconds
c) 37.87 feet

anonymous · Answer

For a just plug in the time value. It is correct.
For b note that you will have a max height when the acceleration stops. When acceleration is equal to 0. Since acceleration would be the first derivative of the equation given, derive it. 

1/2 is the exact value.

Now to find what that max height is, use t=1/2