Question

Solve the linear equation:

Answer 1

\[-6x+6-7(x+1)=6x-7\]

Answer 2

First distribute the 7 into the brackets. let me know what you get.

Answer 3

-6x+6-7x-7=6x-7?

Answer 4

correct. now, we need to get all the terms containing x on the same side of the equality. I suggest adding 6x to each side. what do you get?

Answer 5

Or sorry... subtract 6x on each side.

Answer 6

less work that way

Answer 7

-6x-7x-7=-12x-7

Answer 8

not quite. we should get:\[-6x+6-7x-7-6x=6x-6x-7\]Notice that 6x-6x=0 on the right, giving:\[-6x+6-7x-7-6x=7\]

Answer 9

damn typos today:
-6x+6-7x-7-6x=-7

Answer 10

so far so good?

Answer 11

yes

Answer 12

Now collect all your like terms on the left.

Answer 13

\[(-6x-7x)+(6-7)=-7\]what do you get?

Answer 14

-13x-1=-7

Answer 15

correct

Answer 16

now we need to get rid of the -1 on the left in order to isolate x. To do this, we add 1 to both sides. let me know what you get.

Answer 17

-13x=-6

Answer 18

yep. now solve for x. divide both sides by -13.

Answer 19

wait we missed a term

Answer 20

\[(-6x-7x-6x)+(6-7)=-7\]we forgot the 6x from earlier.

Answer 21

Oh, I did that, haha I was wondering why I was confused!

Answer 22

so we have
-19x=-6

Answer 23

now divide out the -19 on both sides. sorry for the confusion :P

Answer 24

no worries (:
6/19

Answer 25

yeah, looks good now.

Answer 26

I'll triple check

Answer 27

yeah...it's good.

Answer 28

lol, thank you!!

Answer 29

I also have another question

Answer 30

sure

Answer 31

Okay, for this equation: \[5\left[ 7x-4-3(x+1) \right]=-7x-2\] would I distribute the -3 first then distribute the 5?

Answer 32

yes.

Answer 33

\[5(7x-4-3x-3)=-7x-2\]

Answer 34

then distribute the 5. collect like terms. isolate x. solve for x.

Answer 35

Okay !Thank you!

Answer 36

I got 33/27 did I do something wrong?

Answer 37

no that's what I get too

Answer 38

you can simplify the fraction a bit. \[\frac{33}{27}=\frac{11}{9}\]

Answer 39

Yep!! :D Thanks so much!

Answer 40

your welcome :)

Answer 41

you're* typo...lol