An object A of mass 'm' is connected to an object B of mass 'M' through the light pulley by a light thread. The object A is at rest on a horizontal rough table. The object B is suspended from the pulley. The objects A and B began to move after being released. Let the gravitational acceleration be 'g', and let the coefficient of sliding friction between the object A and the table be 'k'.

Q : After the objects are released, how much of the total mechanical energy of A and B is lost in the first second?

Question

An object A of mass 'm' is connected to an object B of mass 'M' through the light pulley by a light thread. The object A is at rest on a horizontal rough table. The object B is suspended from the pulley. The objects A and B began to move after being released. Let the gravitational acceleration be 'g', and let the coefficient of sliding friction between the object A and the table be 'k'.

Q : After the objects are released, how much of the total mechanical energy of A and B is lost in the first second?

anonymous · Answer

mechanical energy lost = work done by friction

anonymous · Answer

the answer is $$\frac{ g^2km(M-km) }{2(m+M) }$$ but how can we solve this?

anonymous · Answer

work done by friction = force of friction * displacement in first second

find both

anonymous · Answer

make a Free Body Diagram

anonymous · Answer

pls show the solution to me

anonymous · Answer

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