Question

attach file

Answer 1

Not sure but I'm wondering if you have to individually get the limit of each function separately and then plug them in into the equation you are asked for. For example you would add the two limits for the first one

Answer 2

how?

Answer 3

for a it says the limit of the function as you approach 1 from the left side.

Answer 4

for f(x) that would be 3
for g(x) that would be 5

so wouldn't it be

3+5 for a)

Answer 5

\[a) \lim_{x \rightarrow 1^{-}}\]

Answer 6

\[1^{-}\]write equation than plug x= 1(negative)?

Answer 7

no that means the limit of x approaches 1 from the left side,

Negative means left
Positive means right

there's a jump discontinuity in x=1 so you will have two values. One different values that you approach from the left and one different from you approach from the right.

Answer 8

ok,tk

Answer 9

This is for a)

I run through the line starting from the left side and stop when x=1

whatever value i get is the limit for x=1 as it approaches from the left side

Answer 10

Can I get some feedback @Callisto

Answer 11

ok

Answer 12

Understand?

Answer 13

b,c and d I able do my own,TK

Answer 14

yes I Understand

Answer 15

i did feedback

Answer 16

1) 5 + 3

Answer 17

2) 4 + 2* 1

Answer 18

do you get the pattern?

Answer 19

no

Answer 20

lim x->1- f(x) + g(x) = (lim x->1- f(x)) + (lim x->1- g(x))

Answer 21

lim x->1+ f(x) + g(x) = (lim x->1+ f(x)) + (lim x->1+ g(x))

Answer 22

tk

Answer 23

I try give you a medal, but don' let me do it

Answer 24

no probs ... can you do the other problem?
lim x->1+ f(x) * g(x) = (lim x->1+ f(x)) * (lim x->1+ g(x))

Answer 25

c) 3*5=15?

Answer 26

yep ..

Answer 27

TK,I have to go

Answer 28

seeya