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Mathematics 8 Online
OpenStudy (anonymous):

Solve PLEASE!!!

OpenStudy (anonymous):

\[2\sin x-\sqrt{3}=0\]

OpenStudy (lgbasallote):

solve for x?

OpenStudy (anonymous):

yes

OpenStudy (lgbasallote):

try starting by adding both sides by \(\sqrt 3\) what do yu get?

OpenStudy (lgbasallote):

you*

OpenStudy (anonymous):

\[2\sin x=\sqrt{3}\]

OpenStudy (lgbasallote):

good. now divide both sides by 2

OpenStudy (anonymous):

\[\sin x =\sqrt{\frac{ 3 }{ 2 }}\]

OpenStudy (lgbasallote):

no. the square root is just on 3...2 has no square root symbol \[\sin x = \frac{\sqrt 3}{2}\] now take the arcsin of both sides

OpenStudy (anonymous):

square root is just on 3

OpenStudy (lgbasallote):

....that's what i said o.O

OpenStudy (anonymous):

posted at the same time :)

OpenStudy (lgbasallote):

righhttt

OpenStudy (lgbasallote):

anyway @Lulu212 do you have the value of \[\sin^{-1} (\frac{\sqrt 3}{2})\]

OpenStudy (anonymous):

pi/3

OpenStudy (lgbasallote):

okay... here's a hint @Lulu212 |dw:1345819226851:dw| does that help?

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