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\[2\sin x-\sqrt{3}=0\]
solve for x?
yes
try starting by adding both sides by \(\sqrt 3\) what do yu get?
you*
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\[2\sin x=\sqrt{3}\]
good. now divide both sides by 2
\[\sin x =\sqrt{\frac{ 3 }{ 2 }}\]
no. the square root is just on 3...2 has no square root symbol \[\sin x = \frac{\sqrt 3}{2}\] now take the arcsin of both sides
square root is just on 3
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....that's what i said o.O
posted at the same time :)
righhttt
anyway @Lulu212 do you have the value of \[\sin^{-1} (\frac{\sqrt 3}{2})\]
pi/3
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okay... here's a hint @Lulu212 |dw:1345819226851:dw| does that help?
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