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OpenStudy (anonymous):
3. What is the sum of a 6-term geometric sequence if the first term is 11, the last term is –11,264 and the common ratio is –4?
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OpenStudy (cwrw238):
sum of n terms = a1 . r^n - 1
-------
r - 1
OpenStudy (anonymous):
ok gimme a sec to try and figure it out.Is that a1 times r^n-1?
OpenStudy (cwrw238):
yes a1*(r^n - 1)
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Evert time I do it I get 9013.4
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OpenStudy (anonymous):
Every*
OpenStudy (cwrw238):
11*((-4)^6 - 1) / -5 ?
OpenStudy (cwrw238):
i make that -9009
OpenStudy (anonymous):
Yeah but I put (-4^6-1)
OpenStudy (anonymous):
Now my calculator says 9011.2
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OpenStudy (cwrw238):
r = -4 so its (-4)^6
OpenStudy (cwrw238):
on most calculators you need to enter the brackets around the -4
OpenStudy (anonymous):
That's what i did differently the second time and i got 9011.2
OpenStudy (cwrw238):
hmm - idk how you got that
the way i did it was
(-4)^6 = -1 = * 11 = / (-5) =
OpenStudy (anonymous):
Ok im gunna try it again.
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OpenStudy (cwrw238):
problem is - calculators vary
OpenStudy (anonymous):
I finally got it! Thanks :)
OpenStudy (cwrw238):
good - ur welcome
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