Mathematics
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OpenStudy (firejay5):
Solve each equation: Please be clear and make on sense on solving equation with/without instructions:
5(6 - 4X) = X + 21
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OpenStudy (lgbasallote):
first, distribute 5 into (6-4x)
you're familiar with the distributive property yes?
OpenStudy (firejay5):
yes
OpenStudy (lgbasallote):
so what is the result when you distribute 5 into (6-4x)
OpenStudy (firejay5):
30 - 20X
OpenStudy (lgbasallote):
good...
so the whole equation will become
30 - 20x = x+ 21
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OpenStudy (lgbasallote):
now add 20x to both sides so that all the x are just on one side
OpenStudy (firejay5):
yes so it's 30 =21X + 21
OpenStudy (lgbasallote):
right. now subtract 21 from both sides
OpenStudy (firejay5):
9 = 21X
OpenStudy (lgbasallote):
and lastly, divide both sides by 21
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OpenStudy (firejay5):
3/7
OpenStudy (lgbasallote):
right!
OpenStudy (firejay5):
is it X = 3/7
OpenStudy (firejay5):
is that the answer
OpenStudy (lgbasallote):
yes x = 3/7 is the final answer
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OpenStudy (firejay5):
can you please show how it would it look like put in for X with the answers
OpenStudy (lgbasallote):
what do you mean?
OpenStudy (firejay5):
enter 3/7 in for X
OpenStudy (lgbasallote):
do you mean for checking?
5(6 - 4(3/7) ) = 3/7 + 21
\[\implies 5(6 - \frac{12}{7} ) = \frac 37 + \frac{147}{7}\]
\[\implies 5(\frac{42}{7} - \frac{12}7) = \frac{150}{7}\]
\[\implies 5(\frac{30}{7}) = \frac{150}{7}\]
\[\implies \frac{150}{7} = \frac{150}7 \checkmark\]
OpenStudy (lgbasallote):
like that?
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OpenStudy (firejay5):
ya thanks! I could figure it out how it worked
OpenStudy (firejay5):
How did you get 147/7
OpenStudy (lgbasallote):
to make 21/1 into a fraction with denominator 7, first divide 7 by 1. the answer is still 7. then, multiply 7 to 21 which is 147
OpenStudy (firejay5):
okay gotcha
OpenStudy (firejay5):
how did you get 42/7
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OpenStudy (lgbasallote):
6/1
divide 7 by 1 hat becomes 7 then multiply to 6..42
OpenStudy (firejay5):
hello dude what's going on #lgbasallote