Question

Helllpp Please ..
simplify the radical expression.
-3√180h^2

Answer 1

What this "h" means?

Answer 2

its just a variable

Answer 3

someone helpp pleasee !

Answer 4

well that was wrong
\[180=9\times 4\times 5\] so
\[\sqrt{180}=\sqrt{9\times 4\times 5}=\sqrt{9}\times \sqrt{4}\times \sqrt{5}=3\times 2\times \sqrt{5}=6\sqrt{5}\]

Answer 5

also \(\sqrt{h^2}=h\) so long as \(h\) is positive

Answer 6

but \[6\sqrt{5}\] isnt a answer for the quiz :/

Answer 7

yes i see
i ignored the \(-3\) out front
not sure how the \(h\) becomes a \(p\) though

Answer 8

you can finish it i am sure

Answer 9

nevermind i looked at the wrong question sorry ! its either
A. \[6\sqrt{5h ^{4}}\]
B. \[-18\sqrt{5h ^{4}}\]
C. \[-18h ^{2}\sqrt{5}\]
D. \[-3h \sqrt{90}\]

Answer 10

maybe the original question is wrong, or maybe i read it incorrectly
i read
\[-3\sqrt{180h^2}\] and the answer is none of these

Answer 11

Are you sure you posted the right question?

Answer 12

question right*

Answer 13

ohh sorry guys im new to this it is \[-3\sqrt{180h ^{4}}\]

Answer 14

it's okay.

Answer 15

\[\sqrt{180h^4}= \sqrt{9\times4\times5 \times h^4}\]
\[\sqrt4, \sqrt9 and \sqrt h^4\] are all perfect squares. Can you give me the answer for each one of them? :)

Answer 16

\[\sqrt{h^4}\] *

Answer 17

\[\sqrt{4} = 2 \]
\[\sqrt{9} = 3 \]
i dont know what this would be \[\sqrt{h}^{4}\]

Answer 18

oh i see now
\(\sqrt{h^4}=\sqrt{(h^2)^2}=h^2\)

Answer 19

im confused

Answer 20

easier to think : two goes in to four twice

Answer 21

is it one of the answers i posted though ?

Answer 22

lets try it with numbers.
lets put \(h=2\) so \(h^4=2^4=2\times 2\times 2\times 2=16\)
then
\[\sqrt{h^4}=\sqrt{16}=4=h^2\]

Answer 23

lets work it out step by step
\[-3\sqrt{180h ^{4}}\]
\[=-3\sqrt{9}\sqrt{4}\sqrt{5}\sqrt{h^4}=-3\times 3\times 2\times h^2\times \sqrt{5}\]
\[=-18h^2\sqrt{5}\]

Answer 24

as usual, it is C
it is always C

Answer 25

ok so you square them of first than multiiply them literally ?