Question

simplify; |3n/n-3..-3|

Answer 1

\[\left|\frac{3n}{n-3}-3\right|\]?

Answer 2

thats it

Answer 3

\[\left|\frac{3n}{n-3}-3\right|\]\[=\left|\frac{3n}{n-3}-3\times1\right|\]\[=\left|\frac{3n}{n-3}-3\times\frac{n-3}{n-3}\right|\]\[=\left|\frac{3n-3(n-3)}{n-3}\right|\]\[=\quad\dots\]

Answer 4

please show how i cancel the top to obtain 9

Answer 5

\[=\left|\frac{3}{n-3}\right|\]\[=\left|\frac{3}{n-3}\times1\right|\]\[=\left|\frac{3}{n-3}\times\frac{n+3}{n+3}\right|\]\[=\left|\frac{3(n+3)}{n^2-9}\right|\]

Answer 6

the correct answer is |9/n-3| in the book

Answer 7

ops -3 times -3 is 9, my last post is all wrong

Answer 8

@UnkleRhaukus check your steps .
\[\left| \frac{3n-3(n-3)}{n-3} \right|=\left| \frac{3n-3n+9)}{n-3} \right| =\left| \frac{9}{n-3} \right|\]

Answer 9

yeah i forgot my times tables for a moment there

Answer 10

thank you very much shubham

Answer 11

:)