simplify |n^2+1/n^2-1..-1|

Question

anonymous · Answer

is that absolute value?  like this:  $\large |\frac{n^2+1}{n^2-1}-1| $  ????

anonymous · Answer

yes sorry thats the best i can display it with the keyboard

anonymous · Answer

ok.... 
so let's just change that "1" to $\large \frac{n^2-1}{n^2-1} $ and subtract those fractions...
can you tell me what you get?

anonymous · Answer

change this "1" : $\large |\frac{n^2+1}{n^2-1}-\color {red}1| $

anonymous · Answer

i get 2/n^2-1

anonymous · Answer

uh... what's the two dots there right before the last "-1" in the original expression?

anonymous · Answer

i was just trying to separate the -1 in the expression. i have a couple more of these and it seems as though 1 method does not work for the other for example |n-1/3n-1/3| can you help with that

anonymous · Answer

if they don't mean anything.... then that's what i got.... so the answer is $\large |\frac{2}{n^2-1}| $ where $\large n \ne \pm1 $

anonymous · Answer

that one is easier than the last one i know

anonymous · Answer

can u use parenthesis to make it clearer?

anonymous · Answer

i dont know what parenthesis are

anonymous · Answer

that's those grouping symbols:  ( )

anonymous · Answer

you know.... when you do a happy face --->   :)

anonymous · Answer

(|n-1/3n|)(|-1/3|) its the same type of question as before

anonymous · Answer

sad face    :(

anonymous · Answer

i'm sorry... i gotta go now.....  maybe one of these guys/gals can help out????

anonymous · Answer

pretty please?

anonymous · Answer

ok

anonymous · Answer

bye bye.... grouping symbol:  :)