Question

In a titration, 19.03 mL of NaOH (0.0940M) was required to titrate 20 ml aliquot solution (of 2.0038 g of unknown acid in 100 ml volumetric flask).
What is the molar mass of the unknown acid?

Answer 1

do we know the stoichiometric relation between the acid and NaOH?

Answer 2

because if we do, we could use it. For example if it's a one to one ratio between NaOH and the acid, that would infer that they have the same number of moles.

Answer 3

We could get the moles of NaOH by multiplying 0.01903L and 0.0940M

Answer 4

once we get the mole, we could have grams/moles to get molar mass

Answer 5

The stoichiometric relation is one to one. And the mole of NaOH is 0.0940 M.
Now, what should I do?

Answer 6

@amishra are you there?

Answer 7

Yeah

Answer 8

Since the ration is 1:1, the mole of NaOH is the same as the mole of the acid. You could just divide the mole by the mass. So grams/mole, and you have your molar mass.