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why cos^-1(cos7pi/6)=5pi/6
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it should be 7pie/6
its given 5pi/6 in the textbook
well,cos(2pi-theta)= cos(theta) isn't it?
cos^-1 (cos 2pie - 5pie/6) = 5pie/6
careful with brackets @Yahoo!
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because \(\cos^{-1}(x)\) does not mean "any number whose cosine is \(x\)" but rather it means " the number between 0 and \(\pi\) whose cosine is \(x\)"
since \(\frac{7\pi}{6}\) is evidently larger than \(\pi\) , it is not in the range of \(\cos^{-1}(x)\) you need another number in the interval \([0,\pi]\) with the same cosine
@drown ,u still have doubts??
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