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Physics 13 Online
OpenStudy (anonymous):

A single 1,300 kg cargo train car is rolling along a train track at 2.0 m/s when 400 kg of coal is dropped vertically into it. What is its velocity right afterward? Assume a closed system. I understand that initial momentum must equal final momentum, which would make the velocity of the coal 6.5 m/s. What I am having difficulty with is determining the final velocity. 1.5 m/s 2.0 m/s 6.5 m/s 0.0011 m/s

OpenStudy (anonymous):

WElcome to open study

OpenStudy (anonymous):

First find initial momentum

OpenStudy (anonymous):

Initial momentum should be 2,600 Kg x m/s since the mass is 1,300 kg and the velocity is 2.0 m/s.

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

Now, new mass=1300kg+400kg=1700kg

OpenStudy (anonymous):

So, initial momentum=final momentum 2600 = 1700*v v=1.5m/s

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

Ok got it. To get the final velocity it would be initial momentum divided by the new mass. Thanks.

OpenStudy (anonymous):

WELcomx

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