If A = {positive integers divisible by 2} and B = {integers}, what is A ∩ B? { } {2, 4, 6, 8 …} {2, 4, 6, 8, 10} {1, 2, 3, 4, 5 …}
the answer is A
@TheMind No. @Gabylovesyou do you know what the intersection operator means?
no i don't @vf321
{2, 4, 6, 8 …}
Okay. The intersection operator \(\cap\) means, quite literally, the intersection of the venn diagrams which represent each set that's being operated on.
intersection indicates comon elements among the two sets so
So \(\left\{ 1,2,3 \right\}\cap\left\{ 3,4,5\right\}=\left\{ {3} \right\}\)
Do you see why? If you draw the Venn diagrams, |dw:1345915932888:dw| 3 is the only one in the middle.
a={2,4,6,8,10,12,14....} b={1,2,3,4,5,6,7...} a intersection b={2,4,6,8,10....}
@shaik0124 how so?
intersection gives common elments among two sets
kk @vf321
@Gabylovesyou if your question was answered please close the question (top-left corner, under "Mathematics")
it wasnt @vf321 i still dont know which one
OKay lets work through this. Do you have an understanding of what an intersection is now?
yes
Okay. Do you agree that the set of all integers looks like this:\[\left\{...-2,-1,0,1,2,...\right\}\]?
yessssss
okay. Good. Now I have a quick question for you. Do you agree that "all positive integers divisible by 2" are also integers? 'Cause that means that the set which contains the former is a SUBSET of the latter.
Or, in Venn diagrams, with A = All integers, and B = All positive ints divisible by 2, do you see why:|dw:1345916865916:dw|
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