Question

Really quick clarification please help

Answer 1

Can anyone please teach me how to solve this?

Answer 2

I want to know how to solve it by paper and by calculator.. :(

Answer 3

use base change formula ..it will be log2/log3

Answer 4

what do you mean... log(base3)2 is equal to log2/log3..?

Answer 5

\[\log _{a}B= \frac{ \log B }{ \log a }\]

Answer 6

yes... is it clear?

Answer 7

what do you mean by "solve" ??? do you mean to find the approximate numeric value?

Answer 8

well for example, i can't solve this:

Answer 9

put the values of log 2 and log 3 then calculate it's ratio

Answer 10

\[\frac{ \log 4 }{ \log 2}- \frac{ \log 3 }{ \log 2 }\] similarly use the base change formula

Answer 11

@isabella1205 is it clear?

Answer 12

so that's this is the problem: \(\large log_34-log_32 \) ???
you're correct that it's \(\large log_32 \).... that's as EXACTLY the answer... so is the question you want it in base 10 so you can get an approximate value of the answer?

Answer 13

@ghazi isn't that a very long procedure though? I'll get decimals, and how do I turn that into log form?

Answer 14

take the LCM above you'll get \[\frac{ \log4-\log3 }{ \log2 }\]

Answer 15

either you can use this \[\log a - \log b= \log (a/b)\] or put the numeric values

Answer 16

what if I have a base number?

Answer 17

whenever you have a base number use base change formula that i mentioned above

Answer 18

alrightt

Answer 19

thank you so much!

Answer 20

:)