Question

8^2/3...simplify

Answer 1

64/3

Answer 2

OR \[21\frac{ 1 }{ 3 }\]

Answer 3

you probably should use parens
8^(2/3)

this means take the cube root then square the answer.
(or square 8 and then find the cube root)

Can you find the cube root of 8?

Answer 4

yeah I got it .. Thanx

Answer 5

To find the cube root of 8 factor 8 into its primes and look for triples.

Answer 6

I took 2 cube and cancle it with 3 out side the root

Answer 7

although I would write it like this

\[ 8^{\frac{2}{3}}= (8^{\frac{1}{3}})^2 \]
then replace 8 with
\[ 8= 2^3 \]
\[ ((2^3)^{\frac{1}{3}})^2 = (2^{\frac{3}{3}})^2= (2^1)^2= 2^2=4\]

Answer 8

If that makes any sense....

Answer 9

what about my method? was it correct?

Answer 10

if you left out the root sign

the problem is
\[ 8^{\frac{2}{3}} \]
and you can replace the 8 with
\[ (2^3)^{\frac{2}{3}} \]
now you can multiply the exponents (cancel the 3's)

Answer 11

But your main idea is correct. the cube cancels the cube root.

Answer 12

ok