Question

Solve for T, where 0≤T≤5
-4π^2cos2πt=0

Answer 1

Do you know how to calculate the period of the function?

Answer 2

T = 2pi/k where k is a constant
in this case u are having an equation which is simple harmonic motion..
k = 2 so
T = pi

Answer 3

If the function is cos 2pi t, k is = 2pi, so the period is 1

Answer 4

oo yea k was 2pi sorry ... sleepy me~ lolz guess i shud go sleep

Answer 5

didnt see the pi lolx

Answer 6

Is mary even in on this?

Answer 7

I know the answer to the problem (it's t= 1/4, 3/4, 5/4,7/4,9/4,11/4,13/4,15/4,17/4) I just don't understand how you get there

Answer 8

if you plot cos( x) it looks like this

so you want your 2 pi t equal to those values