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Mathematics 15 Online
OpenStudy (anonymous):

Six different boys and four different girls are to be seated in a row of ten seats. How many seating arrangements are possible if no two girls may sit next to each other?

OpenStudy (anonymous):

6!4! 6x4x5x3x4x2x3x1x2x1 = 17,280

OpenStudy (anonymous):

I'm sorry but that doesn't seem to be right. The answer was supposed to be 7! x 5! Can you explain your steps?

OpenStudy (anonymous):

I guess the formula would be P = n! / (n1!x n2! x ...nk!) implies: 10! / (6! x 4!) = 210 ?

OpenStudy (anonymous):

7! x 5! is the answer?

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