Six different boys and four different girls are to be seated in a row of ten seats. How many seating arrangements are possible if no two girls may sit next to each other?

Question

anonymous · Answer

6!4!
6x4x5x3x4x2x3x1x2x1 = 17,280

anonymous · Answer

I'm sorry but that doesn't seem to be right.
The answer was supposed to be 7! x 5!
Can you explain your steps?

anonymous · Answer

I guess the formula would be P = n! / (n1!x n2! x ...nk!) 

implies: 10! / (6! x 4!) = 210 ?

anonymous · Answer

7! x 5! is the answer?