Question

23-7x-3x(greater than or equal to sign)-11 Please Help

Answer 1

\[\huge 23 - 7x - 3x \ge -11?\]
this sunds fishy

Answer 2

sounds*

Answer 3

lol really?

Answer 4

can you help?

Answer 5

so is that the question?

Answer 6

yeah thats the question

Answer 7

first combine - 7x and -3x what do you get?

Answer 8

am i adding?

Answer 9

depends what you mean...

Answer 10

like with the -7x and -3x so am i subtracting? or adding?

Answer 11

like i said...depends what you mean...we can only know if what you're thinking is right or wrong if you tell me what you get for -7x -3x

Answer 12

-10

Answer 13

and the x?

Answer 14

-10x?

Answer 15

yes

Answer 16

right ....

Answer 17

so the equation becomes \[\implies 23 - 10x \ge -11\]
now add 10x to both sides

Answer 18

okay im doing it now

Answer 19

-1

Answer 20

\[23>1\]

Answer 21

messed up on the sign

Answer 22

i have no idea what you just did.... o.O

Answer 23

well actually i do

Answer 24

lol me either

Answer 25

1) i said add -10x to BOTH sides..not just the left side
2) you cant combine -11 and -10 x
3) even if you can combine -11 and -10x it should be -21 not 1

Answer 26

oh wait...my number 2 and 3 are wrong

Answer 27

2) you cant combine -11 and 10x
3) even if you can combine -11 and 10x it should be -1 not 1

Answer 28

yeah i caught that

Answer 29

soo whats next after that? Because now i have 23-1

Answer 30

no you dont

Answer 31

ughhh im so confused so what do i have

Answer 32

let's start from the top
\[23 - 10x \ge -11\]
add 10x to both sides. what do you get?

Answer 33

remember those three things i said

Answer 34

right and i get -1

Answer 35

let me give a demonstration...
\[1 - 2x \ge 3\]
if i add 2x to both sides i get
\[\implies 1 - 2x + 2x \ge 3 + 2x\]
now combine like terms
\[\implies 1 \ge 3 + 2x\]
now subtract 3 from both sides
\[\implies 1 -3 \ge 3 + 2x - 3\]
combine like terms
\[\implies -2 \ge 2x\]
divide both sides by 2
\[\implies -1 \ge x\]
or simply \(x \le -1\)
got it now?

Answer 36

its not really the same thing because that one is simple an dthis on eis not so i cant really relate t that example

Answer 37

oh it's very similar i assure you... because i added 2x here...same way as i am instructing you to add 10x there

Answer 38

and i did

Answer 39

you keep combining -11 and 10x...but you see i didnt combine 3 and 2x

Answer 40

so add 10x to the 23?

Answer 41

did i combine 2x to 1?

Answer 42

no..

Answer 43

exactly

Answer 44

okay then idk

Answer 45

here's another one \[30 - 24x \ge -15\]
add 24x to both sides
\[30 - 24x + 24x \ge -15 + 24x\]
combine
\[30 \ge -15 + 24x\]
add 15 to both sides
\[30 + 15 \ge -15 + 24x + 15\]
combine like terms
\[45 \ge 24x\]
divide both sides by 24
\[\frac{45}{24} \ge x\]
is that still simple?

Answer 46

and btw..just so you know...i used the exact same scenario as the question

\[23 - 10x \ge -11\]
and
\[30 - 24x \ge -15\]
see the similarity?

Answer 47

okay yeah.. then its [23>-11+10x\]

Answer 48

without the {}

Answer 49

right

Answer 50

now add 11 to both sides

Answer 51

final answer 34 over 10 >x

Answer 52

hmm close... \[\frac{34}{10} \ge x\]

Answer 53

yeah like thAT..

Answer 54

Whew!!! That took forever but thank you for not giving up on me :)

Answer 55

haha i never do :DD