integrate (9-3x^2+4x^3 -9x^4+5x^5 )

Question

australopithecus · Answer

split the integral up and use the basic rules

mathslover · Answer

$$\huge{\int ({9-3x^2+4x^3 -9x^4+5x^5})dx}$$

anonymous · Answer

integrate it one by one..

australopithecus · Answer

$$\int\limits_{}^{}(f(x) - g(x))dx = \int\limits_{}^{}f(x)dx - \int\limits_{}^{}g(x)dx$$

mathslover · Answer

hmn I am going to try that... wait guys

lgbasallote · Answer

just take the antiderivative. it's easier and faster

australopithecus · Answer

$$\int\limits_{}^{}x^ndx = \frac{x^{n+1}}{n+1}$$

australopithecus · Answer

$$\int\limits_{}^{}Cdx  = C(x)$$

where C is a constant,

that is all you need to know to solve this problem

mathslover · Answer

$$\large{9-\frac{3x^3}{3}+\frac{4x^4}{4}-\frac{9x^5}{5}+\frac{5x^6}{6}+C}$$

australopithecus · Answer

also don't forget + C

mathslover · Answer

I can simplify this.. further

australopithecus · Answer

you made a mistake

mathslover · Answer

m i right?

australopithecus · Answer

see rule above

mathslover · Answer

you mean to say m wrong somewhere? @Australopithecus

australopithecus · Answer

yes Look at the rule just above your answer

mathslover · Answer

will there be 9x?

anonymous · Answer

when you integrate 9 its 9x

australopithecus · Answer

:L I just wanted someone to read my post haha

anonymous · Answer

and the rest are correct

mathslover · Answer

so it will be :
$$\huge{{9x-\frac{3x^3}{3}+\frac{4x^4}{4}-\frac{9x^5}{5}+\frac{5x^6}{6}+C}}$$

australopithecus · Answer

You took that away from me Omniscience

mathslover · Answer

thanks a lot to both ..

shane_b · Answer

Yes...now just simplify it :)

mathslover · Answer

oh k so it will be:
$$\huge{9x-x^3+x^4-\frac{9x^5}{5}+\frac{5x^6}{6}+C}$$

mathslover · Answer

thanks guys

australopithecus · Answer

You can always check your integrals with wolfram alpha but sometimes your answer might look different

australopithecus · Answer

so just be aware

anonymous · Answer

or just differentiate it to see if it matches

lgbasallote · Answer

i emvy you @mathslover you have so much people replying to your integral question...my questions are barren

australopithecus · Answer

some of your questions drive me crazy :)

lgbasallote · Answer

whuuut? but they're just algebra o.O

anonymous · Answer

the easier the question the faster it will get a respond from alot of people ;)

australopithecus · Answer

Yeah you are posting laplace transforms right? I have no idea what they are