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8/v^-3
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you want to simplify?
they want it done using the quotient rule
derivative?
yes
ok we know that \[\frac{d}{dx} \frac{f(x)}{g(x)}\ \ \ \ \ \ =\frac{g(x)\times f'(x)-f(x)\times g'(x)}{(g(x))^2}\] could you use this to find the derivative? here f(x)=8 and \(g(x)=v^{-3}\)
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yes.. so would i use 8^3/v
you have \( \large \frac{8}{v^{-3}}\) just f(x)=8 and \(g(x)=v^{-3}\)
yes.. so how would i finish the problem then? its been a couple of weeks since ive done this!
ok what's the derivative of 8 and v^(-3)? with respect to v
@tyesha ??
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