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Mathematics 7 Online
OpenStudy (anonymous):

8/v^-3

OpenStudy (ash2326):

you want to simplify?

OpenStudy (anonymous):

they want it done using the quotient rule

OpenStudy (ash2326):

derivative?

OpenStudy (anonymous):

yes

OpenStudy (ash2326):

ok we know that \[\frac{d}{dx} \frac{f(x)}{g(x)}\ \ \ \ \ \ =\frac{g(x)\times f'(x)-f(x)\times g'(x)}{(g(x))^2}\] could you use this to find the derivative? here f(x)=8 and \(g(x)=v^{-3}\)

OpenStudy (anonymous):

yes.. so would i use 8^3/v

OpenStudy (ash2326):

you have \( \large \frac{8}{v^{-3}}\) just f(x)=8 and \(g(x)=v^{-3}\)

OpenStudy (anonymous):

yes.. so how would i finish the problem then? its been a couple of weeks since ive done this!

OpenStudy (ash2326):

ok what's the derivative of 8 and v^(-3)? with respect to v

OpenStudy (ash2326):

@tyesha ??

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